Klein Gischau - village in Beetzendorf, Saxony-Anhalt. Article “Klein Gischau” in German Wikipedia has 45.1 points for quality (as of July 1, 2025). The article contains 31 references and 10 sections.
Since the creation of article “Klein Gischau”, its content was written by 14 registered users of German Wikipedia and edited by 14 registered Wikipedia users in all languages.
The article is cited 26 times in German Wikipedia and cited 26 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | German: #807983 11.2019 |
Global: #5363893 05.2008 |
| Best Rank | German: #21472 10.2021 |
Global: #349667 10.2021 |
On 28 January 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 2025–26 UEFA Champions League, Nipah virus, Doomsday Clock, UEFA Champions League, Elena Rybakina, Donald Trump, 2026 European Men's Handball Championship, killing of Alex Pretti, Kristi Noem, deaths in 2026.
In German Wikipedia the most popular articles on that day were: Whitney Houston, Fall Gil Ofarim, Gil Ofarim, Handball-Europameisterschaft der Männer 2026, Der neue Freund, Tova Friedman, Sven Schulze (Politiker, 1979), Liste der größten Auslegerbrücken, Bobbi Kristina Brown, Patricia Aulitzky.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(19.17+44.29+14.29+47.62+100)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
